Test your microbiology knowledge with this free mock test on bacterial identification methods. This quiz includes 100 practice questions focusing on biochemical, cultural, and molecular techniques used in clinical laboratories. Ideal for ASCP MLS and medical laboratory exam preparation.
Free mock test with 100 MCQs on bacterial identification methods . Practice key biochemical, culture-based, and molecular lab techniques for ASCP MLS exam prep.
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ASCP MLS Exam MCQs Chapter 28
Welcome to the Microbiology – Bacterial Identification Methods Mock Test . This quiz is designed for medical laboratory students, MLS/MLT exam candidates, and professionals who want to strengthen their understanding of bacterial identification techniques used in diagnostic microbiology.
This mock test contains 100 multiple-choice questions (MCQs) that cover a wide range of laboratory methods.
Our Bacterial identification methods Mock Test is specifically designed for candidates appearing in ASCP MLS, AMT MLT/MT, AIMS, CSMLS, IBMS, HAAD/DOH, DHA, and MOH exams. This mock test mirrors the structure, difficulty level, and question style you can expect in the actual examination.
Why Take This Mock Test? Biochemical tests: catalase, oxidase, indole, urease, bile esculin, CAMP, hippurate hydrolysis.
Selective & differential media: MacConkey agar, mannitol salt agar, chromogenic agar.
Special identification techniques: D-test, reverse CAMP test, string test, India ink.
Rapid & automated methods: API systems, MALDI-TOF MS, VITEK.
Molecular techniques: 16S rRNA sequencing, PCR/NAAT, whole-genome sequencing.
These practice questions will help you test your preparation for exams like ASCP MLS, AMT, and other international lab certifications . Each question is formatted in MCQ style with four options , just like the real exam.
Take this test to: ✅ Review essential bacterial identification techniques. ✅ Strengthen your microbiology exam preparation. ✅ Boost confidence before the ASCP MLS Exam .
Good luck — let’s begin your mock test on bacterial identification methods!
Who Should Use This Mock Test? Medical Laboratory Scientists and Technicians
Microbiology Students
Professionals preparing for international laboratory certification exams
Anyone seeking to strengthen their knowledge of bacterial identification methods
How to Use This Mock Test Effectively Simulate Exam Conditions: Attempt the test in one sitting without referring to notes.
Track Your Time: Keep within the allotted time limit to build speed.
Review Explanations: Study the answer explanations to strengthen understanding.
Repeat for Retention: Re-attempt after revision to measure improvement.
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ASCP Exam Questions
Which test is used to differentiate Streptococcus pneumoniae from other alpha-hemolytic streptococci?
Bile solubility test is a key test to differentiate Streptococcus pneumoniae (bile-soluble) from other alpha-hemolytic streptococci (e.g., Streptococcus viridans group, which are bile-insoluble). When exposed to bile salts (e.g., sodium deoxycholate), S. pneumoniae lyses, leading to dissolution of the colony or clearing of turbidity in a broth culture.
b) Hippurate hydrolysis: Used to identify Streptococcus agalactiae (Group B streptococcus), which is hippurate-positive.
c) VP test (Voges-Proskauer): Used to detect acetoin production, e.g., to differentiate Klebsiella (VP-positive) from E. coli (VP-negative).
d) Nitrate reduction: Used to identify bacteria that reduce nitrate to nitrite (e.g., E. coli , Pseudomonas ).
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ASCP Exam Questions
Which of the following is used to differentiate Micrococcus from Staphylococcus ?
Micrococcus species are modified oxidase-positive (also known as microdase or tetramethyl-p-phenylenediamine dihydrochloride test positive), while Staphylococcus species are modified oxidase-negative. This is a key test to differentiate them.
Both Micrococcus and Staphylococcus are catalase-positive (a), so the catalase test does not differentiate them.
The coagulase test (c) is used to identify Staphylococcus aureus (coagulase-positive) from other staphylococci (coagulase-negative), but it does not help distinguish Staphylococcus from Micrococcus (as Micrococcus is coagulase-negative).
Bacitracin susceptibility (d) is sometimes used (Micrococcus is susceptible, Staphylococcus is resistant), but the modified oxidase test is more reliable and specific.
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ASCP Exam Questions
The reagent used in the spot indole test is:
The spot indole test is a rapid method performed by placing a drop of a chemical reagent directly onto bacterial growth on an agar plate or smearing growth on a filter paper soaked with the reagent.
Kovac’s reagent (which contains *p*-dimethylaminobenzaldehyde, HCl, and amyl alcohol) is the specific reagent used for this test. A blue-green color indicates the presence of indole, a positive result.
The other reagents are used for different tests:
b) Oxidase reagent (e.g., tetramethyl-p-phenylenediamine) is used for the oxidase test.
c) 3% Hydrogen peroxide is used for the catalase test.
d) 1% Alpha-naphthol is part of Barritt’s reagents A and B used in the Voges-Proskauer (VP) test.
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ASCP Exam Questions
Which of the following organisms is bile-esculin positive but does NOT grow in 6.5% NaCl?
Bile-esculin positive : This means the organism can hydrolyze esculin in the presence of bile, turning the medium black. Both enterococci and group D streptococci (like Streptococcus bovis ) are bile-esculin positive.
Does NOT grow in 6.5% NaCl : This is the key differentiating factor.
Enterococcus faecium (a) is bile-esculin positive and grows in 6.5% NaCl .
Streptococcus bovis (b) is bile-esculin positive but does NOT grow in 6.5% NaCl .
Streptococcus pneumoniae (c) is bile-esculin negative and does not grow in 6.5% NaCl.
Streptococcus agalactiae (d) is bile-esculin negative and does not grow in 6.5% NaCl.
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ASCP Exam Questions
In blood culture processing, the first step after detecting growth is typically:
In blood culture processing, the first step after detecting growth (e.g., via automated sensors or visual turbidity) is to perform a Gram stain . This rapid test provides immediate, critical information:
Morphology (e.g., gram-positive cocci vs. gram-negative rods).
Arrangement (e.g., clusters, chains, pairs).
Preliminary classification to guide empirical antibiotic therapy and subsequent testing (e.g., biochemical tests, MALDI-TOF, or PCR).
Why not the others?
a) Biochemical testing: Requires pure culture and takes hours to days; it is performed after initial isolation and Gram stain.
b) Serotyping: Used for specific organisms (e.g., Salmonella , E. coli ) but is not a first-line test.
d) Whole genome sequencing: Highly specialized, time-consuming, and not routine for initial identification.
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ASCP Exam Questions
Biochemical test plates like the substrate panels help identify bacteria by:
Biochemical test plates (e.g., API strips, Biolog panels) contain multiple substrates (sugars, amino acids, enzymes) that produce visual changes (e.g., color shifts, gas production, precipitation) when metabolized by bacteria. These patterns are compared to databases to identify species based on their metabolic capabilities.
Why not the others?
a) Genetic profiling: Involves DNA sequencing (e.g., 16S rRNA), not biochemical reactions.
c) Measuring turbidity only: Turbidity indicates growth but not specific substrate use; visual cues (color) are key.
d) Only discerning Gram type: Determined by staining, not biochemical panels.
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ASCP Exam Questions
A positive hippurate hydrolysis test is indicative of:
The hippurate hydrolysis test detects the enzyme hippuricase, which hydrolyzes hippurate to benzoic acid and glycine. The glycine is then detected with ninhydrin, turning a deep purple color indicating a positive test.
Streptococcus agalactiae (Group B streptococcus) is positive for hippurate hydrolysis. This is a key test for its identification.
Streptococcus pyogenes (a, Group A streptococcus) is hippurate hydrolysis-negative.
Enterococcus faecalis (c) is variable; some strains may be positive, but it is not a defining characteristic.
Streptococcus pneumoniae (d) is hippurate hydrolysis-negative.
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ASCP Exam Questions
A positive CAMP test is indicative of:
A positive CAMP test is indicative of Streptococcus agalactiae (Group B streptococcus). This test demonstrates the production of a hemolysin by S. agalactiae that synergistically enhances the beta-hemolysis of Staphylococcus aureus , resulting in a characteristic arrowhead-shaped zone of increased hemolysis at the intersection of the two organisms.
a) Streptococcus pyogenes (Group A streptococcus) is identified by bacitracin susceptibility, not the CAMP test.
c) Staphylococcus aureus is used in the CAMP test as the source of beta-toxin but is not identified by it.
d) Enterococcus faecalis is identified by growth in 6.5% NaCl and bile esculin hydrolysis, not the CAMP test.
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ASCP Exam Questions
Selective and differential media support growth and identification by:
Selective inhibition: Suppress the growth of unwanted bacteria using inhibitors (e.g., salts, dyes, antibiotics). Example: Mannitol Salt Agar (7.5% NaCl inhibits non-halophilic bacteria).
Visual differentiation: Incorporate indicators (e.g., pH dyes, substrates) to reveal metabolic traits of growing bacteria. Example: Lactose fermenters turn pink on MacConkey agar due to acid production.
This dual approach allows simultaneous isolation and preliminary identification based on growth and biochemical reactions.
Why not the others?
a) Genotypic methods: Involve DNA/RNA analysis (e.g., PCR), not media-based culture.
b) Direct staining: Techniques like Gram stain visualize morphology but do not support growth.
d) Only inhibiting unwanted bacteria: This describes selective media alone (e.g., Columbia CNA agar), but misses the differential component (e.g., hemolysis patterns on blood agar).
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ASCP Exam Questions
Which of the following is a positive quality control organism for the bile esculin test?
The bile esculin test is used to identify group D streptococci and enterococci, which can hydrolyze esculin to esculetin in the presence of bile. Esculetin then reacts with ferric citrate in the medium to produce a black precipitate , indicating a positive result.
Enterococcus faecalis is a positive quality control organism for this test because it grows in the presence of bile and hydrolyzes esculin, turning the medium black.
Staphylococcus aureus (a) is bile-esculin negative – it may grow but does not hydrolyze esculin.
Streptococcus pyogenes (b) is bile-esculin negative – it does not grow well in bile and does not hydrolyze esculin.
Escherichia coli (d) is bile-esculin negative – it grows in bile but does not hydrolyze esculin (though some strains may weakly react, it is not a reliable positive control).
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ASCP Exam Questions
A positive “string test” is indicative of which genus?
The string test is a rapid, presumptive test used to identify Vibrio cholerae and other Vibrio species. When a loop is mixed with a colony of Vibrio on a slide and then pulled away, it forms a viscous “string” of bacteria (due to the presence of a capsule or slime layer), indicating a positive result.
a) Klebsiella : While Klebsiella species are capsulated and may form viscous strings, the string test is not specific for them; it is primarily associated with Vibrio .
c) Aeromonas : Some Aeromonas species may produce a positive string test, but it is most characteristic of Vibrio .
d) Pseudomonas : Pseudomonas aeruginosa does not typically produce a positive string test.
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ASCP Exam Questions
The ability to grow in 6.5% NaCl is characteristic of:
The ability to grow in 6.5% NaCl broth is a key characteristic of Enterococcus species (e.g., Enterococcus faecalis and Enterococcus faecium ). This test is used to differentiate enterococci from non-enterococcal group D streptococci (like Streptococcus bovis ) and other streptococci.
a) Streptococcus bovis (now classified as Streptococcus gallolyticus ) is a group D streptococcus that is bile-esculin positive but cannot grow in 6.5% NaCl .
b) Streptococcus pneumoniae does not grow in 6.5% NaCl and is optochin-sensitive.
d) Streptococcus pyogenes (Group A streptococcus) does not grow in 6.5% NaCl and is bacitracin-sensitive.
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ASCP Exam Questions
The ability to hydrolyze urea rapidly (within minutes) is a key characteristic of:
Helicobacter pylori is known for its rapid hydrolysis of urea (within minutes) due to its potent urease enzyme. This is the basis for the rapid urease test (e.g., CLOtest®), a key diagnostic method for H. pylori in gastric biopsies.
a) Proteus vulgaris : Produces urease but not as rapidly as H. pylori (typically takes hours).
b) Klebsiella pneumoniae : Some strains are urease-positive, but hydrolysis is slower (hours to days).
d) Pseudomonas aeruginosa : Does not produce urease; it is urease-negative.
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ASCP Exam Questions
The “beaten copper” appearance is characteristic of which organism’s colony?
The “beaten copper” appearance is a characteristic description of colonies of Bacillus anthracis when grown on bicarbonate-containing media under elevated CO₂ conditions. This results in the colonies developing a rough, granular texture with a distinctive metallic sheen resembling beaten copper.
The other options do not exhibit this specific characteristic:
a) Corynebacterium diphtheriae colonies are typically grayish-black on tellurite media.
b) Listeria monocytogenes colonies show a narrow zone of beta-hemolysis on blood agar.
d) Erysipelothrix rhusiopathiae colonies may appear alpha-hemolytic or non-hemolytic and are often small and transparent.
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ASCP Exam Questions
16S rRNA sequencing still performs well even when:
Options check: Culture yields many contaminants → Mixed DNA complicates sequencing
Prior antibiotic use is present → Correct; bacteria may be dead but DNA detectable
Sample is environmental soil → Complex microbiome, needs metagenomics
Bacteria are gram-positive → Not a limitation; both Gram-positive and Gram-negative can be detected
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ASCP Exam Questions
The test used to detect inducible clindamycin resistance in staphylococci is called the:
The D test (double-disk diffusion test) is used to detect inducible clindamycin resistance in staphylococci (and sometimes streptococci). This form of resistance is mediated by the erm gene, which can be induced by erythromycin, leading to cross-resistance to clindamycin.
How it works : An erythromycin disk is placed near a clindamycin disk on an agar plate inoculated with the bacterium. If inducible resistance is present, the zone of inhibition around the clindamycin disk will be flattened or D-shaped adjacent to the erythromycin disk (a positive D test).
a) CAMP test: Used to identify Streptococcus agalactiae (Group B streptococcus) based on enhanced hemolysis.
c) PYR test: Used to identify Streptococcus pyogenes and Enterococcus species based on pyrrolidonyl arylamidase activity.
d) Bacitracin test: Used to identify Streptococcus pyogenes (Group A streptococcus), which is sensitive to bacitracin
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ASCP Exam Questions
Whole-genome sequencing provides:
Whole-genome sequencing (WGS) sequences the entire DNA of an organism, offering the highest level of detail for bacterial identification. It enables:
Strain-level resolution by detecting single-nucleotide polymorphisms (SNPs), gene variations, and mobile genetic elements (e.g., plasmids).
Identification of subspecies and clonal lineages, crucial for outbreak tracking and epidemiology.
Insights into virulence factors, antibiotic resistance genes, and evolutionary relationships.
Why not the others?
a) Only genus-level info: WGS provides far more granular data than genus-level classification (e.g., it can differentiate between identical twins of bacteria).
c) Gram status: This is determined phenotypically (via Gram staining) or inferred from gene content, but WGS itself doesn’t directly “provide” it without analysis.
d) Only biochemical profiles: Biochemical traits are phenotypic; WGS reveals genetic potential (e.g., enzymes for metabolism), but not direct profiles without functional prediction.
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ASCP Exam Questions
Indole, MR, VP, Coagulase
Indole, Methyl red, Voges–Proskauer, Citrate
Indole, Motility, VP, Catalase
Indole, Mannitol, Voges–Proskauer, Catalase
IMViC is a acronym for a series of four biochemical tests used primarily to differentiate members of the Enterobacteriaceae family (e.g., E. coli vs. Klebsiella ). The letters stand for:
I = Indole test (detects tryptophan hydrolysis)
M = Methyl red test (identifies stable acid production from glucose fermentation)
V = Voges–Proskauer test (detects acetoin production, indicating butanediol fermentation)
C = Citrate test (assesses the ability to use citrate as a sole carbon source)
The lowercase “i” is added for ease of pronunciation.
Why not the others?
a) Incorrect: Mannitol and Catalase are not part of IMViC.
c) Incorrect: Motility and Catalase are not included.
d) Incorrect: Coagulase is a test for staphylococci (e.g., S. aureus ), not Enterobacteriaceae.
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ASCP Exam Questions
Multilocus sequence typing (MLST) identifies:
Multilocus sequence typing (MLST) is a molecular technique that identifies sequence types (STs) by sequencing ~450–500 bp internal fragments of 6–8 conserved housekeeping genes (e.g., gapA , recA , gyrB ). Each unique allele combination defines a sequence type, enabling high-resolution strain differentiation for epidemiological studies.
Why not the others?
a) Colony color: A phenotypic trait observed on chromogenic media, not genetic.
c) Only 16S rRNA sequences: 16S rRNA sequencing is used for genus/species identification but lacks the resolution for strain subtyping.
d) Biochemical reaction speed: Part of phenotypic profiling (e.g., API strips), not genetic sequencing.
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ASCP Exam Questions
A positive test for phenylalanine deaminase will result in a:
The phenylalanine deaminase test detects the enzyme that deaminates phenylalanine to form phenylpyruvic acid .
After incubating the organism on phenylalanine agar, ferric chloride is added directly to the culture.
A positive reaction is indicated by the development of a green color (due to the formation of a complex between ferric ions and phenylpyruvic acid).
The other options are incorrect:
b) Red color after adding Barrett’s reagent: Barrett’s reagent is used in the Voges-Proskauer (VP) test for acetoin production (e.g., positive in Klebsiella ).
c) Blue color after adding oxidase reagent: This describes a positive oxidase test (e.g., in Pseudomonas ).
d) Yellow color after adding nitric acid: This occurs in the nitrate reduction test if nitrate is reduced to nitrite (and further confirmed with zinc dust if negative).
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ASCP Exam Questions
Which test is used to identify Streptococcus pneumoniae ?
Optochin susceptibility (ethylhydrocupreine hydrochloride disk test) is a key test for identifying Streptococcus pneumoniae . This bacterium is sensitive to optochin, showing a zone of inhibition around the disk, which distinguishes it from other alpha-hemolytic streptococci (e.g., Streptococcus viridans group) that are resistant.
a) Bacitracin susceptibility: Used to identify Streptococcus pyogenes (Group A streptococcus), which is bacitracin-sensitive.
c) CAMP test: Used to identify Streptococcus agalactiae (Group B streptococcus), which shows enhanced hemolysis with Staphylococcus aureus .
d) PYR test: Used to identify Streptococcus pyogenes (Group A) and Enterococcus species, which hydrolyze L-pyrrolidonyl-β-naphthylamide.
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ASCP Exam Questions
The ONPG test detects the presence of:
The ONPG test (Ortho-Nitrophenyl-β-galactoside) is used to detect the enzyme β-galactosidase . This enzyme hydrolyzes ONPG, a colorless compound, into ortho-nitrophenol (which is yellow) and galactose. A yellow color indicates a positive test.
Purpose : The ONPG test helps identify organisms that possess β-galactosidase, which is involved in lactose fermentation. It is particularly useful for differentiating members of the Enterobacteriaceae family (e.g., E. coli is ONPG positive, while some slow lactose-fermenters may be negative).
Other options :
a) Beta-lactamase: Detected by tests like the nitrocefin test (chromogenic cephalosporin test).
c) Cytochrome oxidase: Detected by the oxidase test (e.g., using tetramethyl-p-phenylenediamine).
d) Catalase: Detected by adding hydrogen peroxide to a bacterial colony; effervescence indicates catalase production.
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ASCP Exam Questions
Catalase presence is tested by adding hydrogen peroxide and looking for:
The catalase test detects the enzyme catalase, which breaks down hydrogen peroxide (H₂O₂) into water and oxygen gas. A positive result is indicated by:
This test is crucial for differentiating certain groups of bacteria:
Catalase-positive: Staphylococcus (e.g., S. aureus ).
Catalase-negative: Streptococcus (e.g., S. pyogenes ).
Why not the others?
a) Color change: Seen in tests like oxidase (blue) or indole (pink/red).
c) Colony swelling: Not a standard outcome in catalase testing.
d) Hemolysis: Assessed on blood agar (e.g., alpha, beta, gamma hemolysis), unrelated to catalase.
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ASCP Exam Questions
A gram-negative rod that is oxidase-positive and ferments glucose would be classified as a:
The Vibrionaceae family (which includes genera like Vibrio , Aeromonas , and Photobacterium ) is characterized by being oxidase-positive and capable of glucose fermentation (often with acid production in O/F media). These organisms are facultative anaerobes and are commonly found in aquatic environments.
Why not the other options?
a) Nonfermenter: Nonfermentative gram-negative rods (e.g., Pseudomonas , Acinetobacter ) are typically oxidase-positive (though some exceptions exist) but do not ferment glucose ; they oxidize it instead.
b) Enteric: Members of the Enterobacteriaceae family (enterics) are oxidase-negative and ferment glucose.
d) Fastidious gram-negative rod: This group includes organisms like Haemophilus or Bordetella , which may be oxidase-positive but often require special growth factors and may not ferment glucose robustly (e.g., some utilize carbohydrates via oxidation or are non-fermentative).
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Differential staining used for respiratory pathogens includes:
Respiratory pathogens are diverse and often require differential staining techniques tailored to the suspected organism :
Acid-fast stain (Ziehl-Neelsen or Kinyoun): Used for Mycobacterium tuberculosis (tuberculosis) and other acid-fast bacilli, which resist decolorization due to mycolic acid in their cell walls.
Silver stains (e.g., Gomori methenamine silver, GMS): Used for fungi (Pneumocystis jirovecii , Histoplasma ) and some bacteria.
Direct fluorescent antibody (DFA) stains: For specific pathogens like Legionella or Bordetella pertussis .
Gram stain: Remains foundational but may not detect all respiratory pathogens (e.g., mycobacteria are weakly gram-positive but require acid-fast staining for clear identification).
Why not the others?
a) Gram stain only: Insufficient for pathogens like M. tuberculosis or fungi, which need special stains.
c) None—culture only: Culture is key, but staining guides initial therapy and diagnostic focus.
d) Capsule stain exclusively: Used for encapsulated bacteria (e.g., Cryptococcus or Klebsiella ), but not comprehensive for all respiratory pathogens.
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ASCP Exam Questions
A rapid method distinguishing lactose fermenters from non-fermenters on agar is:
Other options lack this specific differential capability:
a) Blood agar: Differentiates based on hemolysis patterns (alpha/beta/gamma), not lactose fermentation.
b) Mannitol salt agar: Selective for staphylococci and differentiates mannitol fermentation (yellow vs. red zones).
d) Nutrient agar: A general-purpose medium with no indicators for sugar fermentation.
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ASCP Exam Questions
The compound tetramethyl-p-phenylenediamine is used in the:
Tetramethyl-p-phenylenediamine (often abbreviated as TMPD) is the chemical reagent used as the electron donor in the oxidase test. The test identifies bacteria that produce the enzyme cytochrome c oxidase. When the reagent is oxidized by the enzyme, it turns a dark blue-purple color, indicating a positive result.
The other tests use different reagents:
a) Catalase test: Uses hydrogen peroxide (H₂O₂).
b) Coagulase test: Uses rabbit plasma to detect coagulase enzyme.
d) Indole test: Uses Kovac’s reagent (containing p-dimethylaminobenzaldehyde) after bacterial growth in tryptone broth.
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ASCP Exam Questions
Which test is used to distinguish Enterococcus from group D streptococci?
Enterococci (e.g., Enterococcus faecalis , E. faecium ) can grow in 6.5% NaCl broth , while non-enterococcal Group D streptococci (e.g., Streptococcus bovis group, now classified as Streptococcus gallolyticus ) cannot grow in 6.5% NaCl .
Both Enterococcus and Group D streptococci are bile-esculin positive (they blacken bile esculin agar), so that test alone does not distinguish them.
Growth in 6.5% NaCl is a key test to differentiate enterococci (salt-tolerant) from non-enterococcal Group D streptococci (salt-intolerant).
Other options:
b) PYR hydrolysis: Positive for Enterococcus and Streptococcus pyogenes (Group A), but not specific for distinguishing Enterococcus from Group D streptococci (Group D streptococci are PYR-negative).
c) Bacitracin susceptibility: Used to identify Streptococcus pyogenes (Group A), not relevant here.
d) Optochin susceptibility: Used to identify Streptococcus pneumoniae , not relevant.
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ASCP Exam Questions
A positive bile solubility test is characteristic of:
The bile solubility test is a key diagnostic test for Streptococcus pneumoniae . This bacterium is bile-soluble, meaning it lyses when exposed to bile salts (e.g., sodium deoxycholate). In contrast, other alpha-hemolytic streptococci (like Streptococcus viridans group) are bile-insoluble and do not lyse.
a) Streptococcus viridans : Bile-insoluble (test negative).
c) Enterococcus faecalis : Bile-esculin positive but bile-insoluble (does not lyse).
d) Streptococcus agalactiae (Group B streptococcus): Beta-hemolytic and bile-insoluble.
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ASCP Exam Questions
The API (Analytical Profile Index) system helps in identification using:
The API (Analytical Profile Index) system is a commercial, standardized method for bacterial identification based on biochemical test panels . It consists of plastic strips containing multiple microtubes, each holding a specific substrate (e.g., sugars, enzymes, or metabolic indicators). After inoculation with a bacterial sample, the pattern of reactions (e.g., color changes) is interpreted to identify the genus and species.
a) Genetic sequencing: Involves DNA analysis (e.g., 16S rRNA sequencing), not biochemical reactions.
c) Serotyping: Relies on antigen-antibody reactions (e.g., O, H, or K antigens in Salmonella or E. coli ).
d) Phage typing: Uses bacteriophages to infect and lyse specific bacterial strains.
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ASCP Exam Questions
A gram-positive coccus that is novobiocin-resistant is most likely:
The novobiocin susceptibility test is a key test used to differentiate between coagulase-negative staphylococci.
Staphylococcus saprophyticus is characteristically resistant to novobiocin. This feature is a primary method for distinguishing it from other common coagulase-negative staphylococci like Staphylococcus epidermidis .
Staphylococcus epidermidis (b) is susceptible to novobiocin.
Staphylococcus aureus (c) is also susceptible to novobiocin (though its identification focuses more on coagulase and other tests).
Micrococcus luteus (d) is generally susceptible to novobiocin.
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ASCP Exam Questions
A gram-negative rod that is oxidase-positive, nonfermentative, and produces a blue-green pigment is:
Gram-negative rod : It is a Gram-negative bacterium with a rod shape.
Oxidase-positive : P. aeruginosa is oxidase-positive, which is a key test to differentiate it from other nonfermenters.
Nonfermentative : It does not ferment carbohydrates; instead, it oxidizes them (e.g., in O-F medium).
Produces a blue-green pigment : P. aeruginosa produces pyocyanin , a characteristic blue-green pigment that diffuses into the medium. It may also produce pyoverdine (a yellow-green fluorescent pigment).
Why not the others?
a) Acinetobacter baumannii : Nonfermentative and Gram-negative but oxidase-negative and does not produce a blue-green pigment.
b) Stenotrophomonas maltophilia : Nonfermentative and Gram-negative but oxidase-negative and produces a yellow or non-pigmented colony.
d) Burkholderia cepacia : Nonfermentative and oxidase-positive but typically produces yellow, white, or purple pigments, not blue-green.
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ASCP Exam Questions
Which of the following is used to differentiate Proteus mirabilis from Proteus vulgaris ?
This difference in indole production is a key test to differentiate the two species.
Other tests:
b) Urease test: Both P. mirabilis and P. vulgaris are urease-positive.
c) Citrate test: Both can utilize citrate (P. mirabilis is usually citrate-positive, while P. vulgaris is variable).
d) H₂S production: Both produce H₂S (though P. mirabilis typically produces more)
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ASCP Exam Questions
Which test is used to differentiate Klebsiella pneumoniae from Enterobacter cloacae ?
This difference in motility is a key and simple test to distinguish between these two common gram-negative rods, which are both lactose fermenters and share many other biochemical characteristics (e.g., they are typically Voges-Proskauer (VP) positive and citrate positive).
While other tests might show variations, motility is the most reliable and straightforward differentiating feature:
b) Indole: Both are generally indole-negative (though some K. pneumoniae variants may be positive, it is not consistent).
c) Citrate: Both are citrate-positive.
d) Urease: Both are usually urease-positive (though Enterobacter cloacae may be slower or variable).
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ASCP Exam Questions
A gram-negative rod that is urease-positive, motile, and produces H₂S on TSI agar is:
Urease-positive: Proteus mirabilis is famously rapid urease-positive (it can produce a positive result within hours). Klebsiella pneumoniae is also urease-positive, but the other two (E. coli and Providencia stuartii ) are typically urease-negative.
Motile: Proteus mirabilis is highly motile, noted for its “swarming” phenomenon on agar plates. Klebsiella pneumoniae is non-motile. E. coli is motile, and Providencia stuartii can be motile.
Produces H₂S on TSI: This is a critical characteristic. Proteus mirabilis is a notable producer of hydrogen sulfide (H₂S), which blackens the TSI agar slant. Klebsiella pneumoniae , E. coli , and Providencia stuartii do not produce H₂S.
Therefore, only Proteus mirabilis consistently matches all three characteristics: it is urease-positive, motile, and produces H₂S.
Summary of other options:
b) Klebsiella pneumoniae : Urease-positive, but non-motile and H₂S negative .
c) Escherichia coli : Urease-negative , motile, and H₂S negative .
d) Providencia stuartii : Urease-negative , can be motile, and H₂S negative .
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ASCP Exam Questions
Subtyping below species level may involve:
Subtyping below the species level (e.g., strain differentiation) requires methods that detect variations within a species. These include:
Plasmid analysis: Identifying plasmid profiles that vary between strains.
Toxin gene detection: Using PCR to find specific virulence genes (e.g., Shiga toxins in E. coli O157:H7).
Serotyping: Distinguishing strains based on surface antigens (O, H, K antigens in Salmonella or E. coli ).
Molecular techniques: PFGE, MLST, or WGS for high-resolution strain tracking.
These approaches are essential for epidemiology, outbreak investigations, and understanding pathogenicity.
Why not the others?
a) Gram staining alone: Only categorizes bacteria into broad groups (gram-positive/negative), not subtypes.
c) Only culture morphology: Colony traits (e.g., color, shape) are too variable and unreliable for subtyping.
d) Only catalase testing: A basic biochemical test (e.g., distinguishes staphylococci from streptococci) but lacks strain-level specificity.
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ASCP Exam Questions
Immunochromatographic testing identifies pathogens via:
Immunochromatographic testing (e.g., lateral flow assays) uses test strips containing immobilized antibodies that bind to specific pathogen antigens or host antibodies in a sample. This reaction produces a visible line (often colored) for detection. Examples include:
These tests are quick, user-friendly, and require no specialized equipment.
Why not the others?
a) DNA profiling: Involves molecular techniques like PCR or sequencing.
c) Gram staining: A microscopic method using dyes to classify bacteria.
d) Heat fixation patterns: Part of slide preparation for staining, not a diagnostic test.
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ASCP Exam Questions
Which of the following is a nonfermenter?
Nonfermenters are Gram-negative bacteria that do not ferment carbohydrates for energy. Instead, they oxidize sugars (if they use them at all) and are often oxidase-positive.
Pseudomonas aeruginosa is a classic example of a nonfermenter. It produces acid from carbohydrates oxidatively (e.g., in O-F medium) but not fermentatively.
The other options are all fermenters (part of the Enterobacteriaceae family):
a) Escherichia coli : Ferments lactose and other sugars.
b) Klebsiella pneumoniae : Ferments lactose and other sugars.
d) Proteus mirabilis : Ferments glucose (but not lactose) and produces phenylalanine deaminase.
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ASCP Exam Questions
Label-free bacterial identification through Fourier Transform Light Scattering is:
Fourier Transform Light Scattering (FTLS) is a label-free optical technique used for bacterial identification. It works by:
Measuring the angular scattering pattern of light as it interacts with bacterial cells.
Analyzing unique scattering signatures (via Fourier transform) to identify bacteria based on their physical properties (e.g., size, shape, refractive index).
Avoiding the need for dyes, probes, or genetic amplification (making it “label-free”).
Why not the others?
a) Biochemical test: Relies on metabolic reactions (e.g., API strips), not light scattering.
b) Molecular method: Involves DNA/RNA analysis (e.g., PCR, sequencing), not physical light interaction.
d) Staining procedure: Requires dyes (e.g., Gram stain, fluorescent tags) to visualize cells.
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ASCP Exam Questions
Chromogenic media aids identification by:
Chromogenic media contain substrates that release colored compounds when hydrolyzed by specific enzymes produced by target organisms. This results in distinct colony colors for easy identification. Examples include:
MRSA chromogenic agar: Turns pink/mauve for Staphylococcus aureus (due to phosphatase activity).
UTI chromogenic agar: Differentiates E. coli (blue), Enterococcus (turquoise), and other pathogens.
Candida chromogenic agar: Identifies species by colony color (e.g., C. albicans green).
Why not the others?
a) Using antibodies: Immunological methods (e.g., ELISA) use antibodies, not chromogenic media.
c) Sequencing DNA: A molecular technique unrelated to culture-based chromogenic assays.
d) Only inhibiting growth: Selective media inhibit growth, but chromogenic media focus on differentiation via color.
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ASCP Exam Questions
The IMViC pattern for Escherichia coli is:
+, +, –, –
–, –, +, +
+, –, +, –
–, +, –, +
I (Indole test): Positive (+)
M (Methyl red test): Positive (+)
V (Voges-Proskauer test): Negative (–)
C (Citrate test): Negative (–)
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ASCP Exam Questions
Which organism produces a “fried egg” colony morphology on solid media?
Mycoplasma species , including Mycoplasma pneumoniae , lack a cell wall. When grown on specialized solid media (like Eaton’s or PPLO agar), they form colonies that have a dense, opaque central area (the “yolk”) surrounded by a flatter, translucent periphery (the “white”), giving the classic “fried egg” appearance.
The other options do not exhibit this characteristic:
b) Chlamydia trachomatis : This is an obligate intracellular parasite and cannot be cultured on standard solid media; it requires cell cultures.
c) Mycobacterium tuberculosis : Colonies are typically dry, rough, and buff-colored, often described as having a “cauliflower” appearance, not “fried egg.”
d) Nocardia asteroides : Colonies are often chalky, wrinkled, and have a variable appearance, but not the distinct “fried egg” morphology.
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ASCP Exam Questions
Moraxella catarrhalis can be differentiated from Neisseria species by its:
Moraxella catarrhalis can be differentiated from Neisseria species by its production of DNase . M. catarrhalis is DNase-positive, while Neisseria species (e.g., N. gonorrhoeae , N. meningitidis ) are DNase-negative.
Other key differences:
a) Oxidase positivity : Both Moraxella catarrhalis and Neisseria species are oxidase-positive, so this does not differentiate them.
c) Carbohydrate utilization : Moraxella catarrhalis does not ferment carbohydrates (non-fermenter), while pathogenic Neisseria species ferment glucose and/or other sugars. However, DNase is a more straightforward and reliable test for differentiation.
d) Gram stain morphology : Both appear as Gram-negative diplococci, making morphology similar and not sufficient for differentiation.
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ASCP Exam Questions
The IMViC test series is especially useful for identifying:
The IMViC test series (Indole, Methyl red, Voges-Proskauer, Citrate) is specifically designed to differentiate and identify members of the Enterobacteriaceae family , which includes coliforms (e.g., E. coli , Klebsiella , Enterobacter ) and other enteric bacteria. For example:
E. coli : ++– (Indole +, MR +, VP -, Citrate -)
Klebsiella : –++ (Indole -, MR -, VP +, Citrate +)
This pattern helps distinguish between closely related species within this group.
Why not the others?
a) Gram-positive cocci: Identified with tests like catalase, coagulase, or novobiocin susceptibility.
c) Acid-fast bacteria: Identified with acid-fast staining (e.g., Ziehl-Neelsen) and growth characteristics.
d) Spirochetes: Require dark-field microscopy, serology, or molecular methods (e.g., Treponema pallidum ).
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ASCP Exam Questions
A gram-positive bacillus that is catalase-positive, motile at 25°C, and exhibits “tumbling” motility is:
The description matches Listeria monocytogenes :
Gram-positive bacillus : It appears as Gram-positive rods.
Catalase-positive : L. monocytogenes produces catalase.
Motile at 25°C : It exhibits characteristic “tumbling” motility in semi-solid media at room temperature (25°C) due to peritrichous flagella. Notably, it is non-motile at 37°C.
“Tumbling” motility : This is a hallmark of Listeria monocytogenes , observed under microscopy.
Why not the others?
a) Corynebacterium diphtheriae : Catalase-positive but non-motile and does not exhibit tumbling motility.
c) Bacillus cereus : Catalase-positive and motile, but motility is not specifically “tumbling” and it is not enhanced at 25°C (it grows optimally at 30-37°C).
d) Clostridium perfringens : Gram-positive bacillus but catalase-negative (most clostridia lack catalase) and non-motile.
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ASCP Exam Questions
India ink is typically used for:
India ink is primarily used in microbiology for negative staining to visualize capsules around certain microorganisms, such as the yeast Cryptococcus neoformans . In this technique:
The dark, opaque ink provides a background.
The capsule appears as a clear halo around the cell, as it does not absorb the ink.
The cell itself may be stained with a simple dye (e.g., safranin) for contrast.
This method is especially valuable for diagnosing cryptococcal meningitis from cerebrospinal fluid samples.
Why not the others?
a) Acid-fast staining: Uses carbol fuchsin and methylene blue (e.g., for Mycobacterium tuberculosis ).
b) Simple stain only: India ink is not typically used for simple staining; it creates contrast without penetrating the cell or capsule.
d) Gram-negative rod detection: Relies on Gram staining (crystal violet, iodine, safranin), not India ink.
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ASCP Exam Questions
GC content analysis helps in:
GC content analysis measures the proportion of guanine-cytosine base pairs in bacterial DNA. It is used for:
Taxonomic classification: Organisms with similar GC ratios are often genetically related (e.g., Actinobacteria have high GC content, while Firmicutes tend to have low GC content).
Delineating genera or species when combined with other genetic data (e.g., 16S rRNA sequencing).
Why not the others?
a) Assessing peptidoglycan thickness: Determined by Gram staining, not GC content.
c) Determining fermentation pathways: Identified through biochemical tests (e.g., sugar fermentation assays).
d) Differentiating oxidase production: Detected via oxidase test (e.g., using tetramethyl-p-phenylenediamine).
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ASCP Exam Questions
A positive CAMP test shows:
The CAMP test is a microbiological procedure used to identify Group B Streptococci (Streptococcus agalactiae ).
It demonstrates the phenomenon of synergistic hemolysis . The S. agalactiae produces a diffusible extracellular protein (CAMP factor) that interacts with the beta-hemolysin (a sphingomyelinase) produced by Staphylococcus aureus .
When the two organisms are streaked perpendicularly toward each other on a blood agar plate, this interaction results in a distinct arrowhead-shaped zone of enhanced hemolysis where the two exotoxins meet.
The other options are results of different tests:
b) Hydrolysis of hippurate: This is the hippurate hydrolysis test, used to identify Campylobacter jejuni and Group B Streptococci.
c) Reduction of nitrate: This is the nitrate reduction test, used to determine an organism’s ability to reduce nitrate.
d) Production of cytochrome oxidase: This is the oxidase test, used to identify bacteria that produce the enzyme cytochrome c oxidase.
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ASCP Exam Questions
Which of the following is a reliable test for Neisseria gonorrhoeae identification?
Neisseria gonorrhoeae is identified by its carbohydrate fermentation pattern. Specifically:
It ferments glucose (produces acid) but does not ferment maltose, sucrose, or lactose.
This pattern helps distinguish it from other Neisseria species:
Neisseria meningitidis ferments both glucose and maltose.
Neisseria lactamica ferments glucose, maltose, and lactose.
Neisseria sicca ferments glucose, sucrose, and maltose.
Thus, glucose fermentation (without fermentation of maltose, sucrose, or lactose) is a key test for reliable identification of N. gonorrhoeae .
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ASCP Exam Questions
MALDI-TOF identifies bacteria via:
MALDI-TOF (Matrix-Assisted Laser Desorption/Ionization Time-of-Flight) Mass Spectrometry identifies bacteria by:
Ionizing intact bacterial proteins (especially ribosomal proteins) using a laser.
Measuring the time-of-flight of these ions to determine their mass-to-charge ratios .
Comparing the resulting protein spectrum to a database of known bacterial profiles for identification.
Why not the others?
a) DNA sequencing: Involves genetic analysis (e.g., 16S rRNA sequencing), not protein mass.
c) Biochemical reactions: Relies on metabolic tests (e.g., API strips), not physical ion detection.
d) Gram reaction: A staining technique based on cell wall properties, not mass spectrometry.
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ASCP Exam Questions
Which organism is known for its “swarming” motility on blood agar?
Proteus mirabilis is famous for its “swarming” motility on blood agar or other moist surfaces. This distinctive motility is characterized by concentric waves of bacterial growth spreading outward from the initial inoculation site, due to the organism’s high motility and ability to differentiate into elongated, hyper-flagellated swarmer cells.
b) Pseudomonas aeruginosa is motile via a single polar flagellum but does not exhibit swarming; it shows spreading growth with a greenish pigment.
c) Klebsiella pneumoniae is non-motile (lacks flagella) and forms mucoid colonies due to its capsule.
d) Escherichia coli is peritrichously flagellated and motile but does not swarm like Proteus .
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ASCP Exam Questions
For precise strain-level subtyping, molecular techniques may include:
For precise strain-level subtyping (e.g., tracking outbreaks, distinguishing closely related isolates), molecular techniques are essential:
Serotyping: Identifies strains based on surface antigens (e.g., O, H, K antigens in Salmonella or E. coli ), providing a traditional but specific subtype classification.
Whole-genome sequencing (WGS): Offers the highest resolution by comparing entire genomes, detecting single-nucleotide polymorphisms (SNPs), and identifying virulence or resistance genes. It is the gold standard for epidemiological tracing.
Why not the others?
a) Gram stain: Only categorizes bacteria into broad groups (gram-positive/negative) and cannot differentiate strains.
c) Catalase testing: A basic biochemical test (e.g., distinguishes staphylococci from streptococci) but lacks strain-level specificity.
d) Colony morphology: Visual traits (e.g., color, shape) are too variable and unreliable for subtyping strains.
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ASCP Exam Questions
The indole test is used to differentiate:
The indole test detects the production of indole from tryptophan by the enzyme tryptophanase. This test is commonly used to differentiate:
While the indole test can be part of differentiating other genera, its most classic and routine application is distinguishing E. coli (indole-positive) from Klebsiella species (typically indole-negative, though some species like K. oxytoca are indole-positive).
Why not the others?
b) Proteus (indole-negative for P. mirabilis , but positive for P. vulgaris ) and Providencia (indole-positive) can be differentiated, but this is not the primary use.
c) Shigella (most are indole-negative, but S. sonnei is positive) and Salmonella (indole-negative) may vary, but it is not the key test.
d) Enterobacter (indole-negative) and Serratia (indole-negative) are both usually indole-negative, so it is not useful here.
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ASCP Exam Questions
Which of the following is a key characteristic of Pseudomonas aeruginosa ?
Pseudomonas aeruginosa is known for its ability to grow at 42°C , which is a key characteristic used to differentiate it from other Pseudomonas species and similar bacteria. This thermotolerance is often leveraged in selective media or diagnostic protocols.
Why not the others?
a) Lactose fermentation : P. aeruginosa is a non-fermenter (it does not ferment lactose or other sugars). It oxidizes carbohydrates instead, producing a greenish pigment.
b) Oxidase negativity : P. aeruginosa is oxidase-positive , which is a hallmark of many pseudomonads.
d) Nonmotile : P. aeruginosa is highly motile due to a single polar flagellum. Motility is a key trait.
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ASCP Exam Questions
Which of the following tests is used to identify Streptococcus agalactiae ?
The CAMP test is used to identify Streptococcus agalactiae (Group B streptococcus). This bacterium produces a substance that enhances the hemolysis caused by Staphylococcus aureus beta-toxin, resulting in a characteristic arrowhead-shaped zone of hemolysis.
a) Bacitracin susceptibility is used to identify Streptococcus pyogenes (Group A streptococcus), which is sensitive to bacitracin.
c) Bile esculin hydrolysis is used to identify group D streptococci and enterococci, which can hydrolyze esculin in the presence of bile.
d) Hippurate hydrolysis is a test that can also be used for Streptococcus agalactiae (it hydrolyzes hippurate), but the CAMP test is more commonly associated and highly specific for its identification.
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ASCP Exam Questions
Which molecular technique is commonly used for bacterial genus-species identification by targeting conserved genetic regions?
16S rRNA gene sequencing is a gold-standard molecular technique for bacterial genus and species identification. It targets the 16S ribosomal RNA gene , which contains highly conserved regions (allowing for broad primer binding) and variable regions (enabling discrimination between species). By comparing the sequenced gene to databases (e.g., NCBI, SILVA), precise taxonomic identification is achieved.
a) MALDI-TOF (Matrix-Assisted Laser Desorption/Ionization Time-of-Flight): This is a proteomic technique that identifies bacteria based on protein profiles, not genetic targeting.
c) Gram staining: A phenotypic, non-molecular method for categorizing bacteria based on cell wall properties.
d) Oxidase test: A biochemical test detecting cytochrome c oxidase activity, not a genetic technique.
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ASCP Exam Questions
NAAT stands for Nucleic Acid Amplification Technique , a molecular method that amplifies specific genetic material (DNA or RNA) for detection. Common examples include:
Polymerase chain reaction (PCR)
Transcription-mediated amplification (TMA)
Loop-mediated isothermal amplification (LAMP)
NAATs are highly sensitive and specific, used to identify pathogens (e.g., Chlamydia trachomatis , Mycobacterium tuberculosis , SARS-CoV-2) directly from clinical samples, often without culture.
Why not the others?
a) Non-Antigenic Agglutination Test: Not a standard term; agglutination tests are serological (antigen-antibody based).
c) Neuro-Acid Antibody Test: Incorrect; no such test exists.
d) Non-culture Anaerobic Assay Technique: Anaerobic bacteria are identified via culture or molecular methods, but NAAT is not limited to anaerobes.
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ASCP Exam Questions
The ability to produce deoxyribonuclease (DNase) is a characteristic of:
Serratia marcescens is well-known for its production of extracellular enzymes, including DNase . The DNase test is a common laboratory test used to help identify this organism. Serratia species will hydrolyze DNA, creating a clear zone around the colony on DNase agar when hydrochloric acid is added.
The other options are not typically associated with DNase production:
b) Shigella sonnei : Shigella species are generally DNase negative.
c) Salmonella Typhi: Salmonella species are typically DNase negative.
d) Yersinia enterocolitica : Yersinia species are not known for DNase production; key tests include motility at 25°C vs. 37°C and urease activity.
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ASCP Exam Questions
A gram-negative coccobacillus that requires both X and V factors for growth is:
Growth factors for Haemophilus species :
H. influenzae → requires both X and V factors .
H. parainfluenzae → requires only V factor , not X.
Bordetella pertussis → does not require X or V factors; grows on Bordet-Gengou or Regan-Lowe agar.
Brucella melitensis → small gram-negative coccobacillus, but does not require X or V factors (grows on enriched media).
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ASCP Exam Questions
Which molecular marker is most widely used in phylogenetic bacterial classification?
The 16S ribosomal RNA (rRNA) gene is the most widely used molecular marker for phylogenetic bacterial classification due to its unique properties:
Ubiquitous: Found in all bacteria.
Highly conserved: Contains regions with slow evolutionary change, allowing broad comparisons across taxa.
Variable regions: Specific segments evolve at higher rates, enabling discrimination between genera and species.
Large databases: Extensive reference libraries (e.g., NCBI, SILVA) facilitate reliable identification.
Why not the others?
a) 23S rRNA: Larger and more variable, but less commonly used due to harder sequencing and fewer reference data.
c) gyrB: Encodes DNA gyrase subunit B; useful for finer speciation but not universal.
d) ITS region: Mainly used for fungal classification (e.g., ITS1/ITS2), not bacteria.
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ASCP Exam Questions
The API20NE strip is primarily used to identify:
The API 20NE (Analytical Profile Index 20 Non-Enteric) system is a standardized biochemical test strip designed specifically for the identification of non-enteric Gram-negative bacilli , such as:
It tests substrates like nitrate reduction, urease, esculin hydrolysis, and carbohydrate oxidations, which are tailored to the metabolic profiles of these organisms.
Why not the others?
a) Enterobacteriaceae: Identified with API 20E (for Enterobacteriaceae and other fermentative Gram-negative rods).
c) Gram-positive cocci: Identified with API Staph (for staphylococci) or API Strep (for streptococci).
d) Anaerobes: Identified with API 20A (for anaerobic bacteria).
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Which of the following is a key test for identifying Vibrio cholerae ?
Vibrio cholerae is oxidase-positive , which is a key initial test to differentiate it from Enterobacteriaceae (e.g., E. coli , Salmonella , Shigella ), which are oxidase-negative. This aligns with its classification as a member of the Vibrionaceae family.
Why not the others?
b) Urease test: V. cholerae is urease-negative (unlike V. parahaemolyticus , which is urease-positive).
c) Citrate test: V. cholerae does not utilize citrate (Simmons citrate agar negative).
d) Phenylalanine deaminase: V. cholerae does not produce phenylalanine deaminase (negative test).
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ASCP Exam Questions
Direct microscopy as an ID method is considered:
Direct microscopy involves examining clinical samples (e.g., sputum, urine, CSF) under a microscope without prior culture. It is a non-culture technique that provides rapid, preliminary identification based on:
Morphology (e.g., gram-positive cocci in chains suggesting Streptococcus ).
Staining characteristics (e.g., acid-fast bacilli indicating Mycobacterium ).
Motility (e.g., darting motility of Campylobacter in stool samples).
This method is invaluable for immediate diagnostic clues and guiding initial treatment.
Why not the others?
a) A serological test: Relies on antigen-antibody reactions (e.g., ELISA), not visual microscopy.
c) A biochemical panel: Requires cultured isolates to test metabolic reactions (e.g., API strips).
d) Molecular sequencing: Involves genetic analysis (e.g., PCR, WGS), not direct visualization.
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ASCP Exam Questions
The optochin disk is used for the identification of:
The optochin (ethylhydrocupreine hydrochloride) disk test is used to identify Streptococcus pneumoniae , which is optochin-sensitive (showing a zone of inhibition around the disk). This helps differentiate it from other alpha-hemolytic streptococci (e.g., Streptococcus viridans group), which are optochin-resistant.
a) Haemophilus influenzae is identified using factors like X and V requirements.
b) Group A beta-hemolytic streptococci (Streptococcus pyogenes ) are identified using bacitracin susceptibility.
d) Enterococcus species are identified by their growth in bile esculin and salt tolerance.
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ASCP Exam Questions
Biolog multiwell plates identify bacteria via:
Biolog multiwell plates (e.g., GEN III MicroPlates) identify bacteria by assessing their metabolic phenotype patterns . Each well contains a different carbon source, chemical sensitivity assay, or pH indicator. The bacteria’s ability to utilize these substrates (measured by tetrazolium dye reduction or color changes) generates a unique metabolic fingerprint, which is compared to a database for identification.
Why not the others?
a) Serotyping: Relies on antigen-antibody reactions, not metabolic activity.
b) Antibiotic resistance: Tested via Kirby-Bauer, MIC, or genetic methods, not primarily through substrate utilization.
d) Gram reaction: Determined by staining, not biochemical metabolism.
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ASCP Exam Questions
The satellite phenomenon is associated with which organism?
The satellite phenomenon refers to the growth of Haemophilus influenzae around colonies of Staphylococcus aureus (or other bacteria that produce NAD [V factor]) on blood agar. Haemophilus influenzae requires both X factor (hemin) and V factor (NAD) for growth. Staphylococcus aureus produces V factor through metabolism, which diffuses into the surrounding agar and allows H. influenzae to grow as tiny “satellite” colonies near the staph colonies.
a) Neisseria meningitidis does not exhibit satellite growth; it grows on chocolate agar and requires iron but not X/V factors.
c) Streptococcus pneumoniae may show alpha-hemolysis but does not require X/V factors or show satellite phenomenon.
d) Staphylococcus aureus is the organism that provides the V factor for satellite growth but is not the one exhibiting the phenomenon.
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ASCP Exam Questions
A gram-negative diplococcus that is oxidase-positive, ferments glucose, but not maltose is:
Gram-negative diplococcus : All Neisseria species and Moraxella catarrhalis share this morphology.
Oxidase-positive : All Neisseria species and Moraxella are oxidase-positive.
Ferments glucose, but not maltose : This is the key differentiating factor:
Neisseria gonorrhoeae ferments glucose (produces acid) but does not ferment maltose .
Neisseria meningitidis (a) ferments both glucose and maltose.
Neisseria lactamica (b) ferments glucose, maltose, and lactose.
Moraxella catarrhalis (d) does not ferment carbohydrates (non-fermenter).
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ASCP Exam Questions
Which of the following is a non-spore-forming, anaerobic gram-positive bacillus?
The other options are incorrect:
a) Clostridium difficile : This is an anaerobic gram-positive bacillus, but it forms spores .
c) Bacillus anthracis : This is a gram-positive bacillus that forms spores , but it is aerobic (not anaerobic).
d) Listeria monocytogenes : This is a gram-positive bacillus that does not form spores , but it is facultative anaerobic (not strictly anaerobic) and often exhibits tumbling motility.
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ASCP Exam Questions
The primary purpose of the satellite test is to identify the requirement for:
The satellite test (or satellite phenomenon) is used to identify bacteria that require V factor (NAD; nicotinamide adenine dinucleotide) for growth. In this test, the bacterium (e.g., Haemophilus influenzae ) is streaked across a blood agar plate, and a streak of Staphylococcus aureus is made perpendicularly. S. aureus produces V factor as a metabolic byproduct, which diffuses into the agar. If the test organism requires V factor, it will grow only in the vicinity of the S. aureus streak, forming “satellite” colonies.
a) X factor (hemin): Required by some Haemophilus species (e.g., H. influenzae requires both X and V factors), but the satellite test specifically detects V factor dependence.
c) Both X and V factors: The satellite test alone identifies V factor requirement; X factor need is tested separately (e.g., porphyrin test).
d) Cysteine: Not relevant; cysteine requirement is associated with other fastidious bacteria like Francisella tularensis .
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Which of the following is a key characteristic of the genus Bacteroides ?
Here’s why the other options are incorrect:
a) Strict aerobe: Bacteroides are obligate anaerobes . They cannot grow in the presence of oxygen.
b) Susceptible to vancomycin: Bacteroides are typically resistant to vancomycin . This resistance is a common feature used to help identify them.
c) Resistant to colistin: Bacteroides are generally susceptible to colistin . Resistance to colistin is more common in other gram-negative bacilli like Proteus and Serratia .
d) Bile-resistant: This is correct. The ability to grow in the presence of 20% bile is a fundamental diagnostic test for members of the Bacteroides group. This trait allows them to colonize the intestinal tract.
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ASCP Exam Questions
The reverse CAMP test is used to identify:
The reverse CAMP test is used to identify Clostridium perfringens . In this test, C. perfringens is streaked perpendicularly to a strain of Staphylococcus aureus that produces beta-hemolysin. C. perfringens produces a phospholipase C (alpha-toxin) that synergistically enhances the hemolysis of S. aureus , resulting in a characteristic “arrowhead” or “box-shaped” zone of hemolysis where the two streaks intersect.
b) Streptococcus agalactiae is identified by the standard CAMP test (positive interaction with S. aureus beta-toxin).
c) Staphylococcus aureus is used as the provider of beta-toxin in both standard and reverse CAMP tests but is not identified by it.
d) Listeria monocytogenes exhibits a positive CAMP test with S. aureus but is not associated with the reverse CAMP test.
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ASCP Exam Questions
The oxidase test detects:
The oxidase test detects the presence of the enzyme cytochrome c oxidase , which is part of the electron transport chain in aerobic respiration. A positive result (e.g., blue-purple color within seconds with tetramethyl-p-phenylenediamine reagent) indicates that the bacterium produces this enzyme.
Why not the others?
a) Catalase enzyme: Detected by the catalase test (bubbles with H₂O₂).
c) Lactose fermentation: Assessed using differential media like MacConkey or EMB agar.
d) Indole production: Detected by the indole test (e.g., Kovac’s reagent turning pink/red).
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ASCP Exam Questions
The test that uses tetramethyl-p-phenylenediamine is the:
The oxidase test uses the reagent tetramethyl-p-phenylenediamine (or sometimes dimethyl-p-phenylenediamine). This reagent serves as an artificial electron donor to cytochrome c oxidase. When the enzyme is present, it oxidizes the reagent, causing it to turn a deep blue or purple color almost immediately upon contact with a bacterial colony.
a) Catalase test: Uses hydrogen peroxide to detect catalase enzyme activity (bubbling indicates positive result).
c) Indole test: Uses Kovac’s reagent (containing p-dimethylaminobenzaldehyde) to detect indole production from tryptophan.
d) Coagulase test: Uses plasma to detect coagulase enzyme activity (clot formation indicates positive result).
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ASCP Exam Questions
Which test is used to differentiate Staphylococcus aureus from other staphylococci?
The coagulase test is used to differentiate Staphylococcus aureus (which is coagulase-positive) from other staphylococci (e.g., Staphylococcus epidermidis , which is coagulase-negative).
a) Oxidase test is used to differentiate Pseudomonas (oxidase-positive) from Enterobacteriaceae (oxidase-negative).
b) Catalase test is used to differentiate staphylococci (catalase-positive) from streptococci (catalase-negative), but it does not differentiate among staphylococci.
d) Optochin susceptibility is used to differentiate Streptococcus pneumoniae (optochin-sensitive) from other alpha-hemolytic streptococci.
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ASCP Exam Questions
Which test is used to detect beta-lactamase production?
The nitrocefin test is a rapid and reliable method to detect beta-lactamase production . Nitrocefin is a chromogenic cephalosporin that changes color from yellow to red when hydrolyzed by beta-lactamase enzymes. This test is commonly used for organisms like Staphylococcus aureus , Haemophilus influenzae , and Neisseria gonorrhoeae to confirm resistance to penicillin and other beta-lactam antibiotics.
a) Oxidase test: Detects cytochrome c oxidase (e.g., in Pseudomonas or Neisseria ).
c) Indole test: Identifies the production of indole from tryptophan (e.g., E. coli is indole-positive).
d) Urease test: Detects the enzyme urease, which hydrolyzes urea to ammonia (e.g., Helicobacter pylori is urease-positive).
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ASCP Exam Questions
Direct examination, growth, and analysis of cultures are:
The process of direct examination (e.g., Gram stain, microscopy), growth (culture on media), and analysis of cultures (biochemical tests, colony morphology) represents the classical, stepwise approach to bacterial identification in traditional microbiology. This sequence allows for:
Rapid preliminary results (e.g., Gram stain from a specimen).
Isolation and purification of organisms via culture.
Definitive identification through phenotypic analysis (e.g., API strips, metabolic assays).
Why not the others?
a) Only molecular steps: Molecular methods (e.g., PCR, sequencing) bypass culture and direct examination in many cases.
c) Immunological tests: These involve antigen-antibody reactions (e.g., ELISA) and are not part of the core cultural sequence.
d) None of the above: Incorrect, as this sequence is the foundation of conventional bacteriology.
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ASCP Exam Questions
The porphyrin test is used to determine the need for which factor in Haemophilus species?
The porphyrin test (δ-aminolevulinic acid / ALA test) is used to check whether a Haemophilus species requires X factor (hemin) for growth.
If the organism can synthesize its own hemin from δ-aminolevulinic acid, the test will be positive (red fluorescence under UV).
Thus:
Positive porphyrin test → organism does not require external X factor (e.g., H. parainfluenzae ).
Negative porphyrin test → organism requires X factor (hemin) (e.g., H. influenzae ).
Options check: X factor (hemin) → ✅ detected by porphyrin test.
V factor (NAD) → not tested by porphyrin test.
Both X and V → wrong, only X factor requirement is assessed.
Neither X nor V → incorrect.
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ASCP Exam Questions
Traditional phenotypic techniques include:
Traditional phenotypic techniques rely on observable physical and metabolic characteristics of bacteria. Key methods include:
Staining (e.g., Gram stain, acid-fast stain) for morphology and cell wall properties.
Culturing on selective/differential media (e.g., MacConkey agar, blood agar) to isolate and observe colony traits.
Biochemical tests (e.g., IMViC, oxidase, catalase) to assess metabolic capabilities.
These methods are foundational in microbiology and remain widely used for initial identification.
Why not the others?
a) Whole-genome sequencing: A genotypic (molecular) technique, not phenotypic.
c) MALDI-TOF only: A proteomic method (analyzing protein spectra), though rapid, it is not “traditional” and bridges phenotypic/genotypic approaches.
d) Only selective media: Selective media are part of culturing but represent just one component; phenotypic identification requires a combination of techniques.
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ASCP Exam Questions
Molecular phylogeny complements phenotypic ID by:
Molecular phylogeny (e.g., 16S rRNA sequencing, multilocus sequence analysis) complements phenotypic identification by:
Providing objective, genetic-based confirmation of species, resolving ambiguities from variable phenotypic traits.
Revealing evolutionary relationships between organisms, which may not align with phenotypic classifications.
Identifying unculturable or fastidious bacteria that are difficult to characterize by traditional methods.
This approach enhances accuracy and reproducibility in bacterial taxonomy.
Why not the others?
a) Being slower than culture: While some molecular methods require time, rapid techniques (e.g., real-time PCR, MALDI-TOF) can be faster than full phenotypic profiling.
c) Ignoring biochemical traits: Molecular data integrates with phenotypic traits for a comprehensive understanding, not ignoring them.
d) Only for viral diagnostics: Molecular phylogeny is widely used for bacteria, fungi, and viruses, not exclusively viruses.
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ASCP Exam Questions
In blood culture identification, colony features help guide:
In blood culture identification, observing colony features (e.g., size, shape, color, hemolysis on blood agar) provides initial clues about the organism, which directly guides the selection of appropriate biochemical tests for confirmation. For example:
Small, alpha-hemolytic colonies may suggest Streptococcus pneumoniae , prompting optochin testing.
Large, mucoid colonies might indicate Klebsiella , leading to tests for capsule production or urease.
Golden-yellow colonies could point to Staphylococcus aureus , triggering coagulase testing.
This step is critical before molecular or proteomic methods (e.g., MALDI-TOF) are applied, as it narrows down the possibilities efficiently.
Why not the others?
a) Staining method only: While Gram stain is the first step, colony features further refine test choices beyond staining.
c) Sequencing directly: Used for ambiguous cases but is not the initial approach due to cost and time.
d) MALDI-TOF exclusively: Often relies on pure cultures grown from colonies, but colony morphology helps prioritize which colonies to analyze.
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ASCP Exam Questions
Oxidase test helps differentiate:
The oxidase test is a key tool to differentiate:
Pseudomonads (e.g., Pseudomonas aeruginosa ), which are oxidase-positive .
Enterobacteriaceae (e.g., E. coli , Klebsiella , Salmonella ), which are oxidase-negative .
This distinction is critical because both groups are gram-negative rods but have different metabolic pathways (e.g., pseudomonads are often aerobic non-fermenters, while enterics are facultative fermenters).
Why not the others?
b) All fermenters vs non-fermenters: Some non-fermenters (e.g., Acinetobacter ) are oxidase-negative, while some fermenters (e.g., Vibrio ) are oxidase-positive. The test does not universally separate these groups.
c) Gram-positive vs Gram-negative: Gram status is determined by staining, not oxidase. Many gram-negative bacteria are oxidase-negative (e.g., Enterobacteriaceae).
d) Only between Streptococci species: Streptococci are gram-positive and generally oxidase-negative; the test is not useful for their differentiation (catalase and hemolysis are used instead).
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ASCP Exam Questions
A catalase-negative, gram-positive coccus that hydrolyzes hippurate is most likely:
Catalase-negative : Rules out staphylococci (e.g., Staphylococcus epidermidis is catalase-positive), so option (d) is incorrect.
Gram-positive coccus : Points to streptococci or enterococci.
Hydrolyzes hippurate : The hippurate hydrolysis test is positive for Streptococcus agalactiae (Group B streptococcus).
Now evaluate the options:
a) Streptococcus pyogenes (Group A): Catalase-negative and gram-positive coccus, but it does not hydrolyze hippurate (hippurate-negative).
b) Streptococcus agalactiae (Group B): Catalase-negative, gram-positive coccus, and hippurate-positive (a key identifying feature).
c) Enterococcus faecalis : Catalase-negative and gram-positive coccus, but it is variable for hippurate hydrolysis (not all strains are positive), and it is primarily identified by growth in 6.5% NaCl and bile esculin hydrolysis.
d) Staphylococcus epidermidis : Gram-positive coccus but catalase-positive (so it does not fit the catalase-negative criterion).
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ASCP Exam Questions
The enzyme detected by the oxidase test is:
The oxidase test detects the presence of the enzyme cytochrome c oxidase , which is part of the electron transport chain in aerobic respiration. The test uses a reagent (e.g., tetramethyl-p-phenylenediamine) that changes color to dark blue or purple when oxidized by this enzyme.
a) Catalase: Detected by the catalase test (bubble production with hydrogen peroxide).
c) Peroxidase: Involved in breaking down peroxides but not detected by the oxidase test.
d) Superoxide dismutase: Converts superoxide radicals to oxygen and hydrogen peroxide but is not related to the oxidase test.
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ASCP Exam Questions
Which test is used to differentiate Acinetobacter from Moraxella ?
Options check: Oxidase test → main differentiator
Motility test → both are non-motile , so not useful.
Growth on MacConkey agar → Acinetobacter grows; Moraxella usually does not, but this is less consistent.
All of the above → incorrect, since motility is not differentiating.
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ASCP Exam Questions
The primary stain used in the acid-fast staining procedure is:
The acid-fast stain (e.g., Ziehl-Neelsen or Kinyoun method) is used to identify organisms with high mycolic acid content in their cell walls, such as Mycobacterium tuberculosis .
Carbol fuchsin is the primary red stain that penetrates the waxy cell wall of acid-fast bacteria. It is applied with heat (in Ziehl-Neelsen) or a detergent (in Kinyoun) to drive the stain into the cells.
After decolorization with acid-alcohol, acid-fast bacteria retain the red color (are acid-fast), while non-acid-fast cells lose the stain and take up the counterstain.
The other stains are used in different contexts:
a) Crystal violet: The primary stain in the Gram stain .
c) Methylene blue: Often used as a simple stain or as a counterstain in other procedures (e.g., in acid-fast staining, some protocols use methylene blue as the counterstain).
d) Safranin: The counterstain in the Gram stain (colors gram-negative bacteria pink/red)
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ASCP Exam Questions
The HACEK group of organisms is most commonly associated with:
The HACEK group (Haemophilus species, Aggregatibacter actinomycetemcomitans , Cardiobacterium hominis , Eikenella corrodens , and Kingella species) are fastidious Gram-negative bacteria that are part of the normal oral flora. They are most commonly associated with bacterial endocarditis , particularly subacute cases. These organisms can enter the bloodstream (e.g., through dental procedures or minor trauma) and colonize damaged heart valves.
a) Urinary tract infections: Typically caused by E. coli , Klebsiella , or other Enterobacteriaceae, not HACEK.
b) Nosocomial pneumonia: Often caused by Pseudomonas , Staphylococcus aureus , or Enterobacteriaceae.
d) Gastroenteritis: Usually caused by pathogens like Salmonella , Campylobacter , or viruses.
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ASCP Exam Questions
Which set of biochemical results is characteristic of Escherichia coli ?
TSI K/A, Gas –, H₂S –, Indole –, Motility –
TSI K/A, Gas +, H₂S +, Indole –, Motility +
TSI A/A, Gas +, H₂S +, Indole +, Motility –
TSI A/A, Gas +, H₂S –, Indole +, Motility +
Escherichia coli has the following characteristic biochemical profile:
TSI (Triple Sugar Iron) agar : Acid slant/acid butt (A/A) with gas production (Gas +), but no H₂S production (H₂S –).
Indole test : Positive (Indole +) due to tryptophanase enzyme.
Motility : Positive (Motility +) as most strains are motile.
This combination is highly typical for E. coli .
Why not the others?
b) TSI K/A (alkaline slant/acid butt) suggests a non-fermenter or slow lactose fermenter; E. coli is a rapid lactose fermenter (A/A). Indole negative and non-motile do not fit E. coli .
c) H₂S positive (e.g., Salmonella or Proteus ) and indole negative do not match E. coli .
d) H₂S positive and motility negative do not align with E. coli (which is H₂S negative and usually motile).
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ASCP Exam Questions
Chromogenic, molecular, immunologic tests are examples of:
Chromogenic, molecular, and immunologic tests represent non-traditional or advanced identification techniques that complement or bypass classical methods:
Chromogenic tests: Use enzyme substrates to produce color changes for specific pathogens (e.g., MRSA chromogenic agar).
Molecular tests (e.g., PCR, sequencing): Detect genetic material (DNA/RNA) for high accuracy and speed.
Immunologic tests (e.g., ELISA, lateral flow): Rely on antigen-antibody interactions for targeted detection.
These methods are faster, often more specific, and can be used directly on samples without always requiring culture.
Why not the others?
a) Phenotypic methods: Refer to traditional techniques like staining, culture, and biochemical reactions (e.g., IMViC).
c) Only culture-based methods: Chromogenic media are culture-based, but molecular and immunologic tests are not.
d) Only Gram-dependent tests: These advanced tests do not rely on Gram staining results; they target specific markers regardless of Gram type.
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ASCP Exam Questions
Which of the following is used to differentiate Listeria monocytogenes from Corynebacterium species?
Listeria monocytogenes is motile at 25°C (room temperature) and exhibits a characteristic “tumbling motility” in semi-solid medium. It is non-motile at 37°C.
Corynebacterium species are non-motile at both 25°C and 37°C.
This difference in motility is a key test to differentiate L. monocytogenes (motile) from Corynebacterium spp. (non-motile).
Other options:
a) Catalase test: Both Listeria monocytogenes and Corynebacterium species are catalase-positive, so it does not differentiate them.
c) Gram stain: Both appear as Gram-positive rods (though Corynebacterium may show club-shaped or palisade arrangements, it is not reliable for differentiation).
d) Hemolysis on blood agar: Listeria monocytogenes shows narrow beta-hemolysis, while some Corynebacterium species (e.g., C. diphtheriae ) may show weak hemolysis, but this is not definitive.
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ASCP Exam Questions
Gamma-hemolytic streptococci that blacken bile esculin agar but do not grow in 6.5% NaCl broth are most likely:
Gamma-hemolytic streptococci that blacken bile esculin agar (indicating esculin hydrolysis) but do not grow in 6.5% NaCl broth are characteristic of non-enterococcal Group D streptococci , specifically the Streptococcus bovis group (now classified as Streptococcus gallolyticus and related species).
They are bile-esculin positive (like enterococci) but fail to grow in high-salt broth (6.5% NaCl), which distinguishes them from enterococci (which do grow in high salt).
Group B streptococci (Streptococcus agalactiae ) are beta-hemolytic and do not typically blacken bile esculin agar.
Enterococci (e.g., Enterococcus faecalis ) are gamma- or alpha-hemolytic, blacken bile esculin agar, and grow in 6.5% NaCl broth .
Streptococcus pneumoniae is alpha-hemolytic, optochin-sensitive, and does not blacken bile esculin agar.
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ASCP Exam Questions
Immunological identification methods rely on detecting:
Immunological identification methods utilize the specific binding between antigens (foreign molecules, often on the microbe’s surface) and antibodies (produced by the host immune system or manufactured). Examples include:
Latex agglutination: Antibodies coated on latex particles clump in the presence of specific antigens (e.g., identifying Streptococcus pyogenes or Cryptococcus ).
Enzyme-linked immunosorbent assay (ELISA): Detects antigens or antibodies using enzyme-linked antibodies that produce a color change.
Immunofluorescence: Fluorescently labeled antibodies bind to antigens for visualization under a microscope (e.g., for Legionella or respiratory viruses).
These methods are highly specific for pathogens and are widely used in diagnostics.
Why not the others?
a) DNA sequences: Identified through molecular methods (e.g., PCR, sequencing).
c) Enzyme activity: Detected via biochemical tests (e.g., catalase, oxidase).
d) Colony color: Observed on culture media as a phenotypic trait, not immunological.
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ASCP Exam Questions
Biochemical tests in 96-well substrates analyze:
Biochemical tests in 96-well microplates (e.g., API strips, Biolog systems) are designed to analyze:
Multiple substrate utilization reactions at once , with each well containing a different substrate (e.g., sugars, amino acids, enzymes).
Metabolic profiles are generated based on color changes or other indicators, allowing high-throughput identification of bacteria.
Why not the others?
a) Morphology: Assessed visually via microscopy or colony characteristics, not biochemical wells.
b) Antibiotic susceptibility: Typically tested via diffusion (Kirby-Bauer) or dilution (MIC) methods, though some automated systems combine both.
d) Gram type: Determined by staining, not biochemical reactions.
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ASCP Exam Questions
The HACEK group of organisms requires which condition for growth?
The HACEK group (Haemophilus species, Aggregatibacter actinomycetemcomitans , Cardiobacterium hominis , Eikenella corrodens , and Kingella species) are fastidious Gram-negative bacteria that are part of the normal oral flora and can cause endocarditis. They typically require 5–10% carbon dioxide (CO₂) for optimal growth in the laboratory. This elevated CO₂ concentration enhances their recovery from clinical specimens, especially blood cultures.
a) Anaerobic environment: HACEK organisms are capnophiles (require CO₂) but are not obligate anaerobes; they grow in aerobic conditions with added CO₂.
c) High salt concentration: Not required; they do not thrive in high-salt environments.
d) Low pH: Not necessary; they grow best at neutral pH.
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ASCP Exam Questions
The ability to hydrolyze esculin in the presence of bile is a characteristic of:
The bile-esculin test is a key diagnostic test used to identify organisms that belong to Group D streptococci (now often classified as enterococci, such as Enterococcus faecalis ) and other Group D streptococci (like Streptococcus bovis group).
These organisms produce an enzyme that hydrolyzes esculin to esculetin. Esculetin then reacts with ferric citrate (in the agar) to form a dark brown or black complex.
The presence of bile (often 40% bile) in the medium helps differentiate these bile-resistant organisms from other streptococci that might hydrolyze esculin but cannot grow in bile.
Why not the others?
a) Group A streptococci (Streptococcus pyogenes ): Cannot hydrolyze esculin in the presence of bile; they are bile-sensitive and do not grow.
b) Group B streptococci (Streptococcus agalactiae ): May hydrolyze esculin weakly but are generally bile-sensitive and do not grow in the presence of bile, so they test negative.
d) Pseudomonas aeruginosa : Does not hydrolyze esculin; it is a non-fermenter and does not typically produce the necessary enzymes.
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ASCP Exam Questions
Dark-field microscopy is most useful for detecting:
Dark-field microscopy is particularly valuable for detecting Treponema pallidum , the causative agent of syphilis, because:
This spirochete is too thin to be easily seen with bright-field microscopy.
Dark-field illumination uses a specialized condenser to scatter light, making the organism appear bright against a dark background.
It allows direct visualization of T. pallidum ‘s characteristic corkscrew motility in clinical specimens (e.g., from primary chancre sores).
Why not the others?
a) E. coli : Readily visible with standard Gram staining and bright-field microscopy.
c) Staphylococcus aureus : Easily identified via Gram stain (gram-positive cocci in clusters) and culture.
d) Bacillus anthracis : Detected using Gram stain (gram-positive rods) and capsule stains; dark-field is not typically needed.
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ASCP Exam Questions
A positive PYR test is useful for the identification of:
The PYR test (L-pyrrolidonyl-β-naphthylamide test) detects the enzyme pyrrolidonyl arylamidase . A positive result (development of a red color after adding the reagent) is useful for identifying:
Streptococcus pyogenes (Group A streptococcus), which is PYR-positive.
Enterococcus species (e.g., Enterococcus faecalis ), which are also PYR-positive.
This test helps differentiate these bacteria from others:
b) Staphylococcus aureus is PYR-negative; Staphylococcus epidermidis is also negative.
c) Neisseria species are oxidase-positive but PYR-negative.
d) Escherichia coli and Klebsiella pneumoniae are both PYR-negative.
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ASCP Exam Questions
DNA–DNA hybridization in bacterial ID serves to:
DNA-DNA hybridization (DDH) is a method used to measure the degree of genetic similarity between two bacterial strains by assessing how well their DNA strands bind (hybridize). It helps determine if organisms belong to the same species (typically ≥70% hybridization with ≤5°C melting temperature difference).
Why not the others?
a) Identify motility: Determined through motility agar or microscopic observation, not DNA binding.
c) Detect catalase: A biochemical test using hydrogen peroxide, not genetic hybridization.
d) Measure growth rate: Assessed via turbidity or colony counts over time, unrelated to DNA comparison.
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ASCP Exam Questions
Phenotypic identification of bacteria is most often supplemented by:
While phenotypic methods (e.g., Gram staining, biochemical tests, culture characteristics) are foundational in microbiology, they have limitations:
Some bacteria are slow-growing, fastidious, or phenotypically ambiguous.
Phenotypic traits can vary within species or be influenced by growth conditions.
Molecular tests like DNA sequencing (e.g., 16S rRNA sequencing for bacteria, ITS for fungi) provide genotype-based identification , offering higher accuracy and resolution. They are routinely used to:
Confirm phenotypic results.
Identify unculturable or rare pathogens.
Resolve discrepancies in phenotypic profiles.
Why not the others?
a) Gram staining alone: Provides preliminary morphology but cannot speciate.
c) Only colony color: Highly subjective and insufficient for identification.
d) Acid-fast staining: Specific for mycobacteria or nocardia, not general supplementation.
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ASCP Exam Questions
Serotyping for bacterial identification involves:
Serotyping is a method of bacterial identification and classification based on the detection of specific surface antigens (such as O, H, K, or Vi antigens) using antibodies that bind to these antigens. For example:
O antigen: Somatic (cell wall) antigen
H antigen: Flagellar antigen
K antigen: Capsular antigen
This technique is commonly used for pathogens like Salmonella , E. coli , Shigella , and Vibrio cholerae to differentiate strains within a species, which is crucial for epidemiology and outbreak investigations.
Why not the others?
a) Genetic sequencing: Involves DNA analysis (e.g., 16S rRNA or WGS), not antigen-antibody reactions.
c) Gram staining: A morphological staining technique that categorizes bacteria based on cell wall properties (gram-positive vs. gram-negative).
d) Optochin sensitivity: A biochemical test used to identify Streptococcus pneumoniae (which is sensitive to optochin), not related to serotyping.
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